Solve 3 3 1 2 If A = show that 0=I\$-VZ=zV where 0 partial41 81z* z. null matrix 31 3-2 1 + 0.

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Question

$$[ 0 ] ( \frac { 1 } { 6 } ) = 10 ^ { 1 } [ 0 - \frac { 1 } { 6 } ] _ { 1 } [ \frac { 18 } { 1 } ) = v ^ { 111 } ( \frac { 18 } { 1 } ) = v 1 ] ^ { 111 }$$

Verify

$\text{false}$

Solution Steps

Multiply $0$ and $\frac{1}{6}$ to get $0$.

$$0=10^{1}\left(0-\frac{1}{6}\right)$$

Calculate $10$ to the power of $1$ and get $10$.

$$0=10\left(0-\frac{1}{6}\right)$$

Subtract $\frac{1}{6}$ from $0$ to get $-\frac{1}{6}$.

$$0=10\left(-\frac{1}{6}\right)$$

Express $10\left(-\frac{1}{6}\right)$ as a single fraction.

$$0=\frac{10\left(-1\right)}{6}$$

Multiply $10$ and $-1$ to get $-10$.

$$0=\frac{-10}{6}$$

Reduce the fraction $\frac{-10}{6}$ to lowest terms by extracting and canceling out $2$.

$$0=-\frac{5}{3}$$

Compare $0$ and $-\frac{5}{3}$.

$$\text{false}$$

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