Question

$$0=L+x\pm x$$

Answer

$$L=-(IM*x^2*p*l*u^2*s^2*n)/m$$

Solution


Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[0=L+\frac{xplus\imath nusx}{m}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[0=L+\frac{{x}^{2}pl{u}^{2}{s}^{2}\imath n}{m}\]
Regroup terms.
\[0=L+\frac{\imath {x}^{2}pl{u}^{2}{s}^{2}n}{m}\]
Subtract \(\frac{\imath {x}^{2}pl{u}^{2}{s}^{2}n}{m}\) from both sides.
\[-\frac{\imath {x}^{2}pl{u}^{2}{s}^{2}n}{m}=L\]
Switch sides.
\[L=-\frac{\imath {x}^{2}pl{u}^{2}{s}^{2}n}{m}\]