Solve 0-10=10-20-20-3-30--4-50-60-70 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$0-10=10-20-20-3-30--4-50-60-70$$

Verify

$\text{false}$

Solution Steps

Subtract $10$ from $0$ to get $-10$.

$$-10=10-20-20-3-30-\left(-4\right)-50-60-70$$

Subtract $20$ from $10$ to get $-10$.

$$-10=-10-20-3-30-\left(-4\right)-50-60-70$$

Subtract $20$ from $-10$ to get $-30$.

$$-10=-30-3-30-\left(-4\right)-50-60-70$$

Subtract $3$ from $-30$ to get $-33$.

$$-10=-33-30-\left(-4\right)-50-60-70$$

Subtract $30$ from $-33$ to get $-63$.

$$-10=-63-\left(-4\right)-50-60-70$$

The opposite of $-4$ is $4$.

$$-10=-63+4-50-60-70$$

Add $-63$ and $4$ to get $-59$.

$$-10=-59-50-60-70$$

Subtract $50$ from $-59$ to get $-109$.

$$-10=-109-60-70$$

Subtract $60$ from $-109$ to get $-169$.

$$-10=-169-70$$

Subtract $70$ from $-169$ to get $-239$.

$$-10=-239$$

Compare $-10$ and $-239$.

$$\text{false}$$