Solve 0045 Kg+2.0003 K g =\ gm | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$0.0045\ Kg+2.0003\ K_{g}=\_gm$$

Evaluate

$\frac{1253gk}{625}$

Differentiate w.r.t. k

$\frac{1253g}{625}$