How to solve 0.10+1.06/30

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 0.10+1.06/30 | Equatix

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$$0.10+1.06/30$$

$\frac{203}{1500}\approx 0.135333333$

Expand $\frac{1.06}{30}$ by multiplying both numerator and the denominator by $100$.

$$0.1+\frac{106}{3000}$$

Reduce the fraction $\frac{106}{3000}$ to lowest terms by extracting and canceling out $2$.

$$0.1+\frac{53}{1500}$$

Convert decimal number $0.1$ to fraction $\frac{1}{10}$.

$$\frac{1}{10}+\frac{53}{1500}$$

Least common multiple of $10$ and $1500$ is $1500$. Convert $\frac{1}{10}$ and $\frac{53}{1500}$ to fractions with denominator $1500$.

$$\frac{150}{1500}+\frac{53}{1500}$$

Since $\frac{150}{1500}$ and $\frac{53}{1500}$ have the same denominator, add them by adding their numerators.

$$\frac{150+53}{1500}$$

Add $150$ and $53$ to get $203$.

$$\frac{203}{1500}$$

$\frac{7 \cdot 29}{3 \cdot 2 ^ {2} \cdot 5 ^ {3}} = 0.13533333333333333$