How to solve 0.12(2x-5)+3x=81

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 0.12(2x-5)+3x=81 | Equatix

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$$0.12(2x-5)+3x=81$$

$x = \frac{680}{27} = 25\frac{5}{27} \approx 25.185185185$

Use the distributive property to multiply $0.12$ by $2x-5$.

$$0.24x-0.6+3x=81$$

Combine $0.24x$ and $3x$ to get $3.24x$.

$$3.24x-0.6=81$$

Add $0.6$ to both sides.

$$3.24x=81+0.6$$

Add $81$ and $0.6$ to get $81.6$.

$$3.24x=81.6$$

Divide both sides by $3.24$.

$$x=\frac{81.6}{3.24}$$

Expand $\frac{81.6}{3.24}$ by multiplying both numerator and the denominator by $100$.

$$x=\frac{8160}{324}$$

Reduce the fraction $\frac{8160}{324}$ to lowest terms by extracting and canceling out $12$.

$$x=\frac{680}{27}$$