Solve 25(4f-3)=0.05(10f-9 WHAT | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$0.25 ( 4 f - 3 ) = 0.05 ( 10 f - 9$$

Solve for f

$f=0.6$

Steps for Solving Linear Equation

Use the distributive property to multiply $0.25$ by $4f-3$.

$$f-0.75=0.05\left(10f-9\right)$$

Use the distributive property to multiply $0.05$ by $10f-9$.

$$f-0.75=0.5f-0.45$$

Subtract $0.5f$ from both sides.

$$f-0.75-0.5f=-0.45$$

Combine $f$ and $-0.5f$ to get $0.5f$.

$$0.5f-0.75=-0.45$$

Add $0.75$ to both sides.

$$0.5f=-0.45+0.75$$

Add $-0.45$ and $0.75$ to get $0.3$.

$$0.5f=0.3$$

Divide both sides by $0.5$.

$$f=\frac{0.3}{0.5}$$

Expand $\frac{0.3}{0.5}$ by multiplying both numerator and the denominator by $10$.

$$f=\frac{3}{5}$$