Solve 0.35(4F-2)=0.02(20F-5) | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$0.35(4F-2)=0.02(20F-5)$$

Solve for F

$F=0.6$

Steps for Solving Linear Equation

Use the distributive property to multiply $0.35$ by $4F-2$.

$$1.4F-0.7=0.02\left(20F-5\right)$$

Use the distributive property to multiply $0.02$ by $20F-5$.

$$1.4F-0.7=0.4F-0.1$$

Subtract $0.4F$ from both sides.

$$1.4F-0.7-0.4F=-0.1$$

Combine $1.4F$ and $-0.4F$ to get $F$.

$$F-0.7=-0.1$$

Add $0.7$ to both sides.

$$F=-0.1+0.7$$

Add $-0.1$ and $0.7$ to get $0.6$.

$$F=0.6$$