$$0.366 \times \frac{ 240 }{ 2.75 } \times ( \log ( \frac{ 2 \times 2.75 }{ 0.08 } ) +0.5 \times \log ( \frac{ 4 \times 2.275+2.75 }{ 4 \times 2.275-2.75 } ) )$$
$\frac{4392\log(\frac{17923125}{2032})}{275}\approx 63.013062589$
$\frac{4392\ln(\frac{17923125}{2032})\log_{10}\left(e\right)}{275}$
