$$0.6 x + 1 - \frac { 1 } { 5 } = 0.28 x + 1 + 0.16$$
Solve for x
$x=1.125$
Steps for Solving Linear Equation
Convert $1$ to fraction $\frac{5}{5}$.
$$0.6x+\frac{5}{5}-\frac{1}{5}=0.28x+1+0.16$$
Since $\frac{5}{5}$ and $\frac{1}{5}$ have the same denominator, subtract them by subtracting their numerators.
$$0.6x+\frac{5-1}{5}=0.28x+1+0.16$$
Subtract $1$ from $5$ to get $4$.
$$0.6x+\frac{4}{5}=0.28x+1+0.16$$
Add $1$ and $0.16$ to get $1.16$.
$$0.6x+\frac{4}{5}=0.28x+1.16$$
Subtract $0.28x$ from both sides.
$$0.6x+\frac{4}{5}-0.28x=1.16$$
Combine $0.6x$ and $-0.28x$ to get $0.32x$.
$$0.32x+\frac{4}{5}=1.16$$
Subtract $\frac{4}{5}$ from both sides.
$$0.32x=1.16-\frac{4}{5}$$
Convert decimal number $1.16$ to fraction $\frac{116}{100}$. Reduce the fraction $\frac{116}{100}$ to lowest terms by extracting and canceling out $4$.
$$0.32x=\frac{29}{25}-\frac{4}{5}$$
Least common multiple of $25$ and $5$ is $25$. Convert $\frac{29}{25}$ and $\frac{4}{5}$ to fractions with denominator $25$.
$$0.32x=\frac{29}{25}-\frac{20}{25}$$
Since $\frac{29}{25}$ and $\frac{20}{25}$ have the same denominator, subtract them by subtracting their numerators.
$$0.32x=\frac{29-20}{25}$$
Subtract $20$ from $29$ to get $9$.
$$0.32x=\frac{9}{25}$$
Divide both sides by $0.32$.
$$x=\frac{\frac{9}{25}}{0.32}$$
Express $\frac{\frac{9}{25}}{0.32}$ as a single fraction.
