How to solve 0.8x+0.2=-6.0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 0.8x+0.2=-6.0 | Equatix

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$$0.8x+0.2=-6.0$$

$x=-7.75$

Subtract $0.2$ from both sides.

$$0.8x=-6-0.2$$

Subtract $0.2$ from $-6$ to get $-6.2$.

$$0.8x=-6.2$$

Divide both sides by $0.8$.

$$x=\frac{-6.2}{0.8}$$

Expand $\frac{-6.2}{0.8}$ by multiplying both numerator and the denominator by $10$.

$$x=\frac{-62}{8}$$

Reduce the fraction $\frac{-62}{8}$ to lowest terms by extracting and canceling out $2$.

$$x=-\frac{31}{4}$$