$$0.9.5(4x-5)^{5}0.75x+5y=; yz=1,2f=0.9x+1; 0.25(4(0.37)-5)=0.75(0.31)+6=$$
$x=\frac{1001}{167},\ x=\frac{156939}{45580},\ \text{false}$
