How to solve 1/10-1/7

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/10-1/7 | Equatix

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$$1/10-1/7$$

$-\frac{3}{70}\approx -0.042857143$

Least common multiple of $10$ and $7$ is $70$. Convert $\frac{1}{10}$ and $\frac{1}{7}$ to fractions with denominator $70$.

$$\frac{7}{70}-\frac{10}{70}$$

Since $\frac{7}{70}$ and $\frac{10}{70}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-10}{70}$$

Subtract $10$ from $7$ to get $-3$.

$$-\frac{3}{70}$$

$-\frac{3}{70} = -0.04285714285714286$