How to solve 1/10(75/600)+1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/10(75/600)+1 | Equatix

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$$1/10(75/600)+1$$

$\frac{81}{80}=1.0125$

Reduce the fraction $\frac{75}{600}$ to lowest terms by extracting and canceling out $75$.

$$\frac{1}{10}\times \frac{1}{8}+1$$

Multiply $\frac{1}{10}$ times $\frac{1}{8}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 1}{10\times 8}+1$$

Do the multiplications in the fraction $\frac{1\times 1}{10\times 8}$.

$$\frac{1}{80}+1$$

Convert $1$ to fraction $\frac{80}{80}$.

$$\frac{1}{80}+\frac{80}{80}$$

Since $\frac{1}{80}$ and $\frac{80}{80}$ have the same denominator, add them by adding their numerators.

$$\frac{1+80}{80}$$

Add $1$ and $80$ to get $81$.

$$\frac{81}{80}$$

$\frac{3 ^ {4}}{2 ^ {4} \cdot 5} = 1\frac{1}{80} = 1.0125$