How to solve 1/10((-75)/600)+1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/10((-75)/600)+1 | Equatix

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Question

$$1/10((-75)/600)+1$$

Evaluate

$\frac{79}{80}=0.9875$

Solution Steps

Reduce the fraction $\frac{-75}{600}$ to lowest terms by extracting and canceling out $75$.

$$\frac{1}{10}\left(-\frac{1}{8}\right)+1$$

Multiply $\frac{1}{10}$ times $-\frac{1}{8}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\left(-1\right)}{10\times 8}+1$$

Do the multiplications in the fraction $\frac{1\left(-1\right)}{10\times 8}$.

$$\frac{-1}{80}+1$$

Fraction $\frac{-1}{80}$ can be rewritten as $-\frac{1}{80}$ by extracting the negative sign.

$$-\frac{1}{80}+1$$

Convert $1$ to fraction $\frac{80}{80}$.

$$-\frac{1}{80}+\frac{80}{80}$$

Since $-\frac{1}{80}$ and $\frac{80}{80}$ have the same denominator, add them by adding their numerators.

$$\frac{-1+80}{80}$$

Add $-1$ and $80$ to get $79$.

$$\frac{79}{80}$$

Show Solution

Factor

$\frac{79}{2 ^ {4} \cdot 5} = 0.9875$