How to solve 1/10((-96)/600)+1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/10((-96)/600)+1 | Equatix

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Question

$$1/10((-96)/600)+1$$

Evaluate

$\frac{123}{125}=0.984$

Solution Steps

Reduce the fraction $\frac{-96}{600}$ to lowest terms by extracting and canceling out $24$.

$$\frac{1}{10}\left(-\frac{4}{25}\right)+1$$

Multiply $\frac{1}{10}$ times $-\frac{4}{25}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\left(-4\right)}{10\times 25}+1$$

Do the multiplications in the fraction $\frac{1\left(-4\right)}{10\times 25}$.

$$\frac{-4}{250}+1$$

Reduce the fraction $\frac{-4}{250}$ to lowest terms by extracting and canceling out $2$.

$$-\frac{2}{125}+1$$

Convert $1$ to fraction $\frac{125}{125}$.

$$-\frac{2}{125}+\frac{125}{125}$$

Since $-\frac{2}{125}$ and $\frac{125}{125}$ have the same denominator, add them by adding their numerators.

$$\frac{-2+125}{125}$$

Add $-2$ and $125$ to get $123$.

$$\frac{123}{125}$$

Show Solution

Factor

$\frac{3 \cdot 41}{5 ^ {3}} = 0.984$