How to solve 1/2+3/10-3/20

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/2+3/10-3/20 | Equatix

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Question

$$1/2+3/10-3/20$$

Evaluate

$\frac{13}{20}=0.65$

Solution Steps

Least common multiple of $2$ and $10$ is $10$. Convert $\frac{1}{2}$ and $\frac{3}{10}$ to fractions with denominator $10$.

$$\frac{5}{10}+\frac{3}{10}-\frac{3}{20}$$

Since $\frac{5}{10}$ and $\frac{3}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{5+3}{10}-\frac{3}{20}$$

Add $5$ and $3$ to get $8$.

$$\frac{8}{10}-\frac{3}{20}$$

Reduce the fraction $\frac{8}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{4}{5}-\frac{3}{20}$$

Least common multiple of $5$ and $20$ is $20$. Convert $\frac{4}{5}$ and $\frac{3}{20}$ to fractions with denominator $20$.

$$\frac{16}{20}-\frac{3}{20}$$

Since $\frac{16}{20}$ and $\frac{3}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-3}{20}$$

Subtract $3$ from $16$ to get $13$.

$$\frac{13}{20}$$

Show Solution

Factor

$\frac{13}{2 ^ {2} \cdot 5} = 0.65$