How to solve 1/3-9/5 imes1/2=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/3-9/5\times1/2= | Equatix

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$$1/3-9/5 \times 1/2=$$

$-\frac{17}{30}\approx -0.566666667$

Multiply $\frac{9}{5}$ and $1$ to get $\frac{9}{5}$.

$$\frac{1}{3}-\frac{\frac{9}{5}}{2}$$

Express $\frac{\frac{9}{5}}{2}$ as a single fraction.

$$\frac{1}{3}-\frac{9}{5\times 2}$$

Multiply $5$ and $2$ to get $10$.

$$\frac{1}{3}-\frac{9}{10}$$

Least common multiple of $3$ and $10$ is $30$. Convert $\frac{1}{3}$ and $\frac{9}{10}$ to fractions with denominator $30$.

$$\frac{10}{30}-\frac{27}{30}$$

Since $\frac{10}{30}$ and $\frac{27}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{10-27}{30}$$

Subtract $27$ from $10$ to get $-17$.

$$-\frac{17}{30}$$

$-\frac{17}{30} = -0.5666666666666667$