$$1/3(2x-1)-1/4(2x+1)=1/2(2-x)$$
$x = \frac{19}{8} = 2\frac{3}{8} = 2.375$
$$\frac{1}{3}\times 2x+\frac{1}{3}\left(-1\right)-\frac{1}{4}\left(2x+1\right)=\frac{1}{2}\left(2-x\right)$$
$$\frac{2}{3}x+\frac{1}{3}\left(-1\right)-\frac{1}{4}\left(2x+1\right)=\frac{1}{2}\left(2-x\right)$$
$$\frac{2}{3}x-\frac{1}{3}-\frac{1}{4}\left(2x+1\right)=\frac{1}{2}\left(2-x\right)$$
$$\frac{2}{3}x-\frac{1}{3}-\frac{1}{4}\times 2x-\frac{1}{4}=\frac{1}{2}\left(2-x\right)$$
$$\frac{2}{3}x-\frac{1}{3}+\frac{-2}{4}x-\frac{1}{4}=\frac{1}{2}\left(2-x\right)$$
$$\frac{2}{3}x-\frac{1}{3}-\frac{1}{2}x-\frac{1}{4}=\frac{1}{2}\left(2-x\right)$$
$$\frac{1}{6}x-\frac{1}{3}-\frac{1}{4}=\frac{1}{2}\left(2-x\right)$$
$$\frac{1}{6}x-\frac{4}{12}-\frac{3}{12}=\frac{1}{2}\left(2-x\right)$$
$$\frac{1}{6}x+\frac{-4-3}{12}=\frac{1}{2}\left(2-x\right)$$
$$\frac{1}{6}x-\frac{7}{12}=\frac{1}{2}\left(2-x\right)$$
$$\frac{1}{6}x-\frac{7}{12}=\frac{1}{2}\times 2+\frac{1}{2}\left(-1\right)x$$
$$\frac{1}{6}x-\frac{7}{12}=1+\frac{1}{2}\left(-1\right)x$$
$$\frac{1}{6}x-\frac{7}{12}=1-\frac{1}{2}x$$
$$\frac{1}{6}x-\frac{7}{12}+\frac{1}{2}x=1$$
$$\frac{2}{3}x-\frac{7}{12}=1$$
$$\frac{2}{3}x=1+\frac{7}{12}$$
$$\frac{2}{3}x=\frac{12}{12}+\frac{7}{12}$$
$$\frac{2}{3}x=\frac{12+7}{12}$$
$$\frac{2}{3}x=\frac{19}{12}$$
$$x=\frac{19}{12}\times \frac{3}{2}$$
$$x=\frac{19\times 3}{12\times 2}$$
$$x=\frac{57}{24}$$
$$x=\frac{19}{8}$$
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