How to solve 1/4(8x-14y)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/4(8x-14y) | Equatix

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Question

$$1/4(8x-14y)$$

Evaluate

$-\frac{7y}{2}+2x$

Solution Steps

Use the distributive property to multiply $\frac{1}{4}$ by $8x-14y$.

$$\frac{1}{4}\times 8x+\frac{1}{4}\left(-14\right)y$$

Multiply $\frac{1}{4}$ and $8$ to get $\frac{8}{4}$.

$$\frac{8}{4}x+\frac{1}{4}\left(-14\right)y$$

Divide $8$ by $4$ to get $2$.

$$2x+\frac{1}{4}\left(-14\right)y$$

Multiply $\frac{1}{4}$ and $-14$ to get $\frac{-14}{4}$.

$$2x+\frac{-14}{4}y$$

Reduce the fraction $\frac{-14}{4}$ to lowest terms by extracting and canceling out $2$.

$$2x-\frac{7}{2}y$$

Show Solution

Expand

$-\frac{7y}{2}+2x$

Solution Steps

Use the distributive property to multiply $\frac{1}{4}$ by $8x-14y$.

$$\frac{1}{4}\times 8x+\frac{1}{4}\left(-14\right)y$$

Multiply $\frac{1}{4}$ and $8$ to get $\frac{8}{4}$.

$$\frac{8}{4}x+\frac{1}{4}\left(-14\right)y$$

Divide $8$ by $4$ to get $2$.

$$2x+\frac{1}{4}\left(-14\right)y$$

Multiply $\frac{1}{4}$ and $-14$ to get $\frac{-14}{4}$.

$$2x+\frac{-14}{4}y$$

Reduce the fraction $\frac{-14}{4}$ to lowest terms by extracting and canceling out $2$.

$$2x-\frac{7}{2}y$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

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Solution Steps

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Solution Steps