How to solve 1/4x-6=1/3x

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/4x-6=1/3x | Equatix

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$$1/4x-6=1/3x$$

$x=-72$

Subtract $\frac{1}{3}x$ from both sides.

$$\frac{1}{4}x-6-\frac{1}{3}x=0$$

Combine $\frac{1}{4}x$ and $-\frac{1}{3}x$ to get $-\frac{1}{12}x$.

$$-\frac{1}{12}x-6=0$$

Add $6$ to both sides. Anything plus zero gives itself.

$$-\frac{1}{12}x=6$$

Multiply both sides by $-12$, the reciprocal of $-\frac{1}{12}$.

$$x=6\left(-12\right)$$

Multiply $6$ and $-12$ to get $-72$.

$$x=-72$$