1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/5-1/6 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$1/5-1/6$$

$\frac{1}{30}\approx 0.033333333$

Least common multiple of $5$ and $6$ is $30$. Convert $\frac{1}{5}$ and $\frac{1}{6}$ to fractions with denominator $30$.

$$\frac{6}{30}-\frac{5}{30}$$

Since $\frac{6}{30}$ and $\frac{5}{30}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{6-5}{30}$$

Subtract $5$ from $6$ to get $1$.

$$\frac{1}{30}$$

$\frac{1}{2 \cdot 3 \cdot 5} = 0.03333333333333333$