How to solve 1/5+3/15+6/25

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/5+3/15+6/25 | Equatix

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$$1/5+3/15+6/25$$

$\frac{16}{25}=0.64$

Reduce the fraction $\frac{3}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{5}+\frac{1}{5}+\frac{6}{25}$$

Since $\frac{1}{5}$ and $\frac{1}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{1+1}{5}+\frac{6}{25}$$

Add $1$ and $1$ to get $2$.

$$\frac{2}{5}+\frac{6}{25}$$

Least common multiple of $5$ and $25$ is $25$. Convert $\frac{2}{5}$ and $\frac{6}{25}$ to fractions with denominator $25$.

$$\frac{10}{25}+\frac{6}{25}$$

Since $\frac{10}{25}$ and $\frac{6}{25}$ have the same denominator, add them by adding their numerators.

$$\frac{10+6}{25}$$

Add $10$ and $6$ to get $16$.

$$\frac{16}{25}$$

$\frac{2 ^ {4}}{5 ^ {2}} = 0.64$