How to solve 1/6+3/2+5/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/6+3/2+5/3 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

$$1/6+3/2+5/3$$

$\frac{10}{3}\approx 3.333333333$

Least common multiple of $6$ and $2$ is $6$. Convert $\frac{1}{6}$ and $\frac{3}{2}$ to fractions with denominator $6$.

$$\frac{1}{6}+\frac{9}{6}+\frac{5}{3}$$

Since $\frac{1}{6}$ and $\frac{9}{6}$ have the same denominator, add them by adding their numerators.

$$\frac{1+9}{6}+\frac{5}{3}$$

Add $1$ and $9$ to get $10$.

$$\frac{10}{6}+\frac{5}{3}$$

Reduce the fraction $\frac{10}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{5}{3}+\frac{5}{3}$$

Since $\frac{5}{3}$ and $\frac{5}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{5+5}{3}$$

Add $5$ and $5$ to get $10$.

$$\frac{10}{3}$$

$\frac{2 \cdot 5}{3} = 3\frac{1}{3} = 3.3333333333333335$