1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/7-1/8 | Equatix

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Question

$$1/7-1/8$$

$\frac{1}{56}\approx 0.017857143$

Least common multiple of $7$ and $8$ is $56$. Convert $\frac{1}{7}$ and $\frac{1}{8}$ to fractions with denominator $56$.

$$\frac{8}{56}-\frac{7}{56}$$

Since $\frac{8}{56}$ and $\frac{7}{56}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-7}{56}$$

Subtract $7$ from $8$ to get $1$.

$$\frac{1}{56}$$

$\frac{1}{2 ^ {3} \cdot 7} = 0.017857142857142856$