1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/7+1/8 | Equatix

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Question

$$1/7+1/8$$

$\frac{15}{56}\approx 0.267857143$

Least common multiple of $7$ and $8$ is $56$. Convert $\frac{1}{7}$ and $\frac{1}{8}$ to fractions with denominator $56$.

$$\frac{8}{56}+\frac{7}{56}$$

Since $\frac{8}{56}$ and $\frac{7}{56}$ have the same denominator, add them by adding their numerators.

$$\frac{8+7}{56}$$

Add $8$ and $7$ to get $15$.

$$\frac{15}{56}$$

$\frac{3 \cdot 5}{2 ^ {3} \cdot 7} = 0.26785714285714285$