How to solve 1/(10(-75/600)+1)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/(10(-75/600)+1) | Equatix

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Question

$$1/(10(-75/600)+1)$$

Evaluate

$-4$

Solution Steps

Reduce the fraction $\frac{-75}{600}$ to lowest terms by extracting and canceling out $75$.

$$\frac{1}{10\left(-\frac{1}{8}\right)+1}$$

Express $10\left(-\frac{1}{8}\right)$ as a single fraction.

$$\frac{1}{\frac{10\left(-1\right)}{8}+1}$$

Multiply $10$ and $-1$ to get $-10$.

$$\frac{1}{\frac{-10}{8}+1}$$

Reduce the fraction $\frac{-10}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{1}{-\frac{5}{4}+1}$$

Convert $1$ to fraction $\frac{4}{4}$.

$$\frac{1}{-\frac{5}{4}+\frac{4}{4}}$$

Since $-\frac{5}{4}$ and $\frac{4}{4}$ have the same denominator, add them by adding their numerators.

$$\frac{1}{\frac{-5+4}{4}}$$

Add $-5$ and $4$ to get $-1$.

$$\frac{1}{-\frac{1}{4}}$$

Divide $1$ by $-\frac{1}{4}$ by multiplying $1$ by the reciprocal of $-\frac{1}{4}$.

$$1\left(-4\right)$$

Multiply $1$ and $-4$ to get $-4$.

$$-4$$

Show Solution

Factor