$$1 \frac { 1 } { 2 } x + \frac { 1 } { 4 } y = 8$$
$x=-\frac{y}{6}+\frac{16}{3}$
$$2\left(1\times 2+1\right)x+1y=32$$
$$2\left(2+1\right)x+1y=32$$
$$2\times 3x+1y=32$$
$$6x+1y=32$$
$$6x=32-y$$
$$\frac{6x}{6}=\frac{32-y}{6}$$
$$x=\frac{32-y}{6}$$
$$x=-\frac{y}{6}+\frac{16}{3}$$
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$y=32-6x$
$$1y=32-6x$$
$$y=-6x+32$$
