Question

$$1\frac{1}{2}x+\frac{5}{8}=\frac{3}{4}x-\frac{1}{8};$$

Answer

x=-3/19

Solution


Simplify  \(\frac{11}{2}x\)  to  \(\frac{11x}{2}\).
\[\frac{11x}{2}+\frac{5}{8}=\frac{3}{4}x-\frac{1}{8}\]
Simplify  \(\frac{3}{4}x\)  to  \(\frac{3x}{4}\).
\[\frac{11x}{2}+\frac{5}{8}=\frac{3x}{4}-\frac{1}{8}\]
Multiply both sides by \(4\) (the LCM of \(2, 4\)).
\[22x+\frac{5}{2}=3x-\frac{1}{2}\]
Subtract \(3x\) from both sides.
\[22x+\frac{5}{2}-3x=-\frac{1}{2}\]
Simplify  \(22x+\frac{5}{2}-3x\)  to  \(19x+\frac{5}{2}\).
\[19x+\frac{5}{2}=-\frac{1}{2}\]
Subtract \(\frac{5}{2}\) from both sides.
\[19x=-\frac{1}{2}-\frac{5}{2}\]
Simplify  \(-\frac{1}{2}-\frac{5}{2}\)  to  \(-3\).
\[19x=-3\]
Divide both sides by \(19\).
\[x=-\frac{3}{19}\]

Decimal Form: -0.157895