How to solve 1 1/7 * 4 1/2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1 1/7 * 4 1/2 | Equatix

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Question

$$1\frac{1}{7}\times4\frac{1}{2}$$

Evaluate

$\frac{36}{7}\approx 5.142857143$

Solution Steps

Multiply $1$ and $7$ to get $7$.

$$\frac{7+1}{7}\times \frac{4\times 2+1}{2}$$

Add $7$ and $1$ to get $8$.

$$\frac{8}{7}\times \frac{4\times 2+1}{2}$$

Multiply $4$ and $2$ to get $8$.

$$\frac{8}{7}\times \frac{8+1}{2}$$

Add $8$ and $1$ to get $9$.

$$\frac{8}{7}\times \frac{9}{2}$$

Multiply $\frac{8}{7}$ times $\frac{9}{2}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{8\times 9}{7\times 2}$$

Do the multiplications in the fraction $\frac{8\times 9}{7\times 2}$.

$$\frac{72}{14}$$

Reduce the fraction $\frac{72}{14}$ to lowest terms by extracting and canceling out $2$.

$$\frac{36}{7}$$

Show Solution

Factor

$\frac{2 ^ {2} \cdot 3 ^ {2}}{7} = 5\frac{1}{7} = 5.142857142857143$