$$1\frac{11}{24}\div\frac{35}{48}-\frac{3}{10}$$
$\frac{17}{10}=1.7$
$$\frac{\left(1\times 24+11\right)\times 48}{24\times 35}-\frac{3}{10}$$
$$\frac{2\left(11+24\right)}{35}-\frac{3}{10}$$
$$\frac{2\times 35}{35}-\frac{3}{10}$$
$$\frac{70}{35}-\frac{3}{10}$$
$$2-\frac{3}{10}$$
$$\frac{20}{10}-\frac{3}{10}$$
$$\frac{20-3}{10}$$
$$\frac{17}{10}$$
Show Solution
Hide Solution
$\frac{17}{2 \cdot 5} = 1\frac{7}{10} = 1.7$