1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1 6/8 = | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1\frac{6}{8}=$$

Evaluate

$\frac{7}{4}=1.75$

Solution Steps

Multiply $1$ and $8$ to get $8$.

$$\frac{8+6}{8}$$

Add $8$ and $6$ to get $14$.

$$\frac{14}{8}$$

Reduce the fraction $\frac{14}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{4}$$

Show Solution

Factor

$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$

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