How to solve (1 7/9) / (4/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (1 7/9) / (4/3) | Equatix

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$$1\frac{7}{9}\div\frac{4}{3}$$

$\frac{4}{3}\approx 1.333333333$

Divide $\frac{1\times 9+7}{9}$ by $\frac{4}{3}$ by multiplying $\frac{1\times 9+7}{9}$ by the reciprocal of $\frac{4}{3}$.

$$\frac{\left(1\times 9+7\right)\times 3}{9\times 4}$$

Cancel out $3$ in both numerator and denominator.

$$\frac{7+9}{3\times 4}$$

Add $7$ and $9$ to get $16$.

$$\frac{16}{3\times 4}$$

Multiply $3$ and $4$ to get $12$.

$$\frac{16}{12}$$

Reduce the fraction $\frac{16}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{4}{3}$$

$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$