Solve 1 - 500 - 40 =; - 10x - 4 =; 2x-8x.B= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1-500-40=; -10x-4=; 2x-8x.B=$$

Solve for x, y

$y=-539$

Solution Steps

Consider the first equation. Combine $2x$ and $-8x$ to get $-6x$.

$$-10x-4=-6x$$

Add $6x$ to both sides.

$$-10x-4+6x=0$$

Combine $-10x$ and $6x$ to get $-4x$.

$$-4x-4=0$$

Add $4$ to both sides. Anything plus zero gives itself.

$$-4x=4$$

Divide both sides by $-4$.

$$x=\frac{4}{-4}$$

Divide $4$ by $-4$ to get $-1$.

$$x=-1$$

Consider the second equation. Subtract $500$ from $1$ to get $-499$.

$$y=-499-40$$

Subtract $40$ from $-499$ to get $-539$.

$$y=-539$$

The system is now solved.

$$x=-1$$ $$y=-539$$