1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1/32 5 | Equatix

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a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1 - \frac { 32 } { 5 }$$

Evaluate

$-\frac{27}{5}=-5.4$

Solution Steps

Convert $1$ to fraction $\frac{5}{5}$.

$$\frac{5}{5}-\frac{32}{5}$$

Since $\frac{5}{5}$ and $\frac{32}{5}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{5-32}{5}$$

Subtract $32$ from $5$ to get $-27$.

$$-\frac{27}{5}$$

Show Solution

Factor

$-\frac{27}{5} = -5\frac{2}{5} = -5.4$

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