$$1(1 \times 4-4 \times 1)-2(2 \times 4-4 \times 1)+6(2 \times 1-1 \times 1)$$
$-2$
$$1\left(4-4\times 1\right)-2\left(2\times 4-4\times 1\right)+6\left(2\times 1-1\times 1\right)$$
$$1\left(4-4\right)-2\left(2\times 4-4\times 1\right)+6\left(2\times 1-1\times 1\right)$$
$$1\times 0-2\left(2\times 4-4\times 1\right)+6\left(2\times 1-1\times 1\right)$$
$$0-2\left(2\times 4-4\times 1\right)+6\left(2\times 1-1\times 1\right)$$
$$0-2\left(8-4\times 1\right)+6\left(2\times 1-1\times 1\right)$$
$$0-2\left(8-4\right)+6\left(2\times 1-1\times 1\right)$$
$$0-2\times 4+6\left(2\times 1-1\times 1\right)$$
$$0-8+6\left(2\times 1-1\times 1\right)$$
$$-8+6\left(2\times 1-1\times 1\right)$$
$$-8+6\left(2-1\times 1\right)$$
$$-8+6\left(2-1\right)$$
$$-8+6\times 1$$
$$-8+6$$
$$-2$$
Show Solution
Hide Solution
