How to solve 1((1)^(2)+1+1)+5=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1((1)^(2)+1+1)+5= | Equatix

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3(r+2s)=2t-4

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Question

$$1( { 1 }^{ 2 } +1+1)+5=$$

Evaluate

$8$

Solution Steps

Calculate $1$ to the power of $2$ and get $1$.

$$1\left(1+1+1\right)+5$$

Add $1$ and $1$ to get $2$.

$$1\left(2+1\right)+5$$

Add $2$ and $1$ to get $3$.

$$1\times 3+5$$

Multiply $1$ and $3$ to get $3$.

$$3+5$$

Add $3$ and $5$ to get $8$.

$$8$$

Show Solution

Factor

$2^{3}$

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