$$1(\frac{3}{4}\times6; \frac{7}{4}\times\frac{6}{1}=\frac{42}{4}=1\frac{2}{4}$$
$x=-\frac{2x_{6}}{3}+\frac{19}{2}$
$x_{6}\neq \frac{51}{4}$
$x_{6}=-\frac{3x}{2}+\frac{57}{4}$
$x\neq 1$
