Solve 1(- 1 3/25) - 2 1/7 + (- 2 1/9)(- 27/790) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1(-1\frac{3}{25})-2\frac{1}{7}+(-2\frac{1}{9})\cdot(-\frac{27}{790})$$

Evaluate

$-\frac{88223}{27650}\approx -3.190705244$

Solution Steps

Multiply $1$ and $25$ to get $25$.

$$1\left(-\frac{25+3}{25}\right)-\frac{2\times 7+1}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Add $25$ and $3$ to get $28$.

$$1\left(-\frac{28}{25}\right)-\frac{2\times 7+1}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Multiply $1$ and $-\frac{28}{25}$ to get $-\frac{28}{25}$.

$$-\frac{28}{25}-\frac{2\times 7+1}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Multiply $2$ and $7$ to get $14$.

$$-\frac{28}{25}-\frac{14+1}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Add $14$ and $1$ to get $15$.

$$-\frac{28}{25}-\frac{15}{7}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Least common multiple of $25$ and $7$ is $175$. Convert $-\frac{28}{25}$ and $\frac{15}{7}$ to fractions with denominator $175$.

$$-\frac{196}{175}-\frac{375}{175}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Since $-\frac{196}{175}$ and $\frac{375}{175}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{-196-375}{175}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Subtract $375$ from $-196$ to get $-571$.

$$-\frac{571}{175}+\left(-\frac{2\times 9+1}{9}\right)\left(-\frac{27}{790}\right)$$

Multiply $2$ and $9$ to get $18$.

$$-\frac{571}{175}+\left(-\frac{18+1}{9}\right)\left(-\frac{27}{790}\right)$$

Add $18$ and $1$ to get $19$.

$$-\frac{571}{175}-\frac{19}{9}\left(-\frac{27}{790}\right)$$

Multiply $-\frac{19}{9}$ times $-\frac{27}{790}$ by multiplying numerator times numerator and denominator times denominator.

$$-\frac{571}{175}+\frac{-19\left(-27\right)}{9\times 790}$$

Do the multiplications in the fraction $\frac{-19\left(-27\right)}{9\times 790}$.

$$-\frac{571}{175}+\frac{513}{7110}$$

Reduce the fraction $\frac{513}{7110}$ to lowest terms by extracting and canceling out $9$.

$$-\frac{571}{175}+\frac{57}{790}$$

Least common multiple of $175$ and $790$ is $27650$. Convert $-\frac{571}{175}$ and $\frac{57}{790}$ to fractions with denominator $27650$.

$$-\frac{90218}{27650}+\frac{1995}{27650}$$

Since $-\frac{90218}{27650}$ and $\frac{1995}{27650}$ have the same denominator, add them by adding their numerators.

$$\frac{-90218+1995}{27650}$$

Add $-90218$ and $1995$ to get $-88223$.

$$-\frac{88223}{27650}$$

Factor

$-\frac{88223}{27650} = -3\frac{5273}{27650} = -3.1907052441229657$