Solve 1 + 2 + 3 + 4; 19 + 200; 320 + 100; 1024 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1+2+3+4; +19+200; +320+100; +1024$$

Sort

$10,\ 219,\ 820,\ 1024$

Solution Steps

Add $1$ and $2$ to get $3$.

$$sort(3+3+4,19+200,720+100,1024)$$

Add $3$ and $3$ to get $6$.

$$sort(6+4,19+200,720+100,1024)$$

Add $6$ and $4$ to get $10$.

$$sort(10,19+200,720+100,1024)$$

Add $19$ and $200$ to get $219$.

$$sort(10,219,720+100,1024)$$

Add $720$ and $100$ to get $820$.

$$sort(10,219,820,1024)$$

The list values are already in order.

$$10,219,820,1024$$

Evaluate

$10,\ 219,\ 820,\ 1024$