How to solve 1+2+3+4+5+6+7+8

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1+2+3+4+5+6+7+8 | Equatix

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3(r+2s)=2t-4

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Question

$$1+2+3+4+5+6+7+8$$

Evaluate

$36$

Solution Steps

Add $1$ and $2$ to get $3$.

$$3+3+4+5+6+7+8$$

Add $3$ and $3$ to get $6$.

$$6+4+5+6+7+8$$

Add $6$ and $4$ to get $10$.

$$10+5+6+7+8$$

Add $10$ and $5$ to get $15$.

$$15+6+7+8$$

Add $15$ and $6$ to get $21$.

$$21+7+8$$

Add $21$ and $7$ to get $28$.

$$28+8$$

Add $28$ and $8$ to get $36$.

$$36$$

Show Solution

Factor

$2^{2}\times 3^{2}$

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