Solve 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1+2+3+4+5+6+7+8=36$$

Verify

$\text{true}$

Solution Steps

Add $1$ and $2$ to get $3$.

$$3+3+4+5+6+7+8=36$$

Add $3$ and $3$ to get $6$.

$$6+4+5+6+7+8=36$$

Add $6$ and $4$ to get $10$.

$$10+5+6+7+8=36$$

Add $10$ and $5$ to get $15$.

$$15+6+7+8=36$$

Add $15$ and $6$ to get $21$.

$$21+7+8=36$$

Add $21$ and $7$ to get $28$.

$$28+8=36$$

Add $28$ and $8$ to get $36$.

$$36=36$$

Compare $36$ and $36$.

$$\text{true}$$