$$1+4x \times 1+4x$$
$8x+1$
$$1+4x+4x$$
$$1+8x$$
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$8$
$$\frac{\mathrm{d}}{\mathrm{d}x}(1+4x+4x)$$
$$\frac{\mathrm{d}}{\mathrm{d}x}(1+8x)$$
$$8x^{1-1}$$
$$8x^{0}$$
$$8\times 1$$
$$8$$