How to solve 1+8-9-5+8x637

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1+8-9-5+8x637 | Equatix

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Question

$$1+8-9-5+8x637$$

Evaluate

$8x_{637}-5$

Show Solution

Differentiate w.r.t. x_637

$8$

Steps Using Derivative Rule for Sum

Add $1$ and $8$ to get $9$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{637}}(9-9-5+8x_{637})$$

Subtract $9$ from $9$ to get $0$.

$$\frac{\mathrm{d}}{\mathrm{d}x_{637}}(-5+8x_{637})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$8x_{637}^{1-1}$$

Subtract $1$ from $1$.

$$8x_{637}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$8\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$8$$

Show Solution

Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. x_637

Steps Using Derivative Rule for Sum