How to solve 1+(3)/(9)=

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1+(3)/(9)= | Equatix

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$$1+ \frac{ 3 }{ 9 } =$$

$\frac{4}{3}\approx 1.333333333$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$1+\frac{1}{3}$$

Convert $1$ to fraction $\frac{3}{3}$.

$$\frac{3}{3}+\frac{1}{3}$$

Since $\frac{3}{3}$ and $\frac{1}{3}$ have the same denominator, add them by adding their numerators.

$$\frac{3+1}{3}$$

Add $3$ and $1$ to get $4$.

$$\frac{4}{3}$$

$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$