1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 1+i/2-i | Equatix

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Unit Circle

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Conic Sections

Sequences & Series

Descriptive Statistics

Eigenvalues & Eigenvectors

Linear Transformations

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$1+i/2-i$$

Evaluate

$1-\frac{1}{2}i=1-0.5i$

Solution Steps

Divide $i$ by $2$ to get $\frac{1}{2}i$.

$$1+\frac{1}{2}i-i$$

Combine the real and imaginary parts.

$$1+\left(\frac{1}{2}-1\right)i$$

Add $\frac{1}{2}$ to $-1$.

$$1-\frac{1}{2}i$$

Show Solution

Real Part

$1$

Solution Steps

Divide $i$ by $2$ to get $\frac{1}{2}i$.

$$Re(1+\frac{1}{2}i-i)$$

Combine the real and imaginary parts in $1+\frac{1}{2}i-i$.

$$Re(1+\left(\frac{1}{2}-1\right)i)$$

Add $\frac{1}{2}$ to $-1$.

$$Re(1-\frac{1}{2}i)$$

The real part of $1-\frac{1}{2}i$ is $1$.

$$1$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Real Part

Solution Steps