Example

3(r+2s)=2t-4
a⋅(b-2)=3b
3(r+2s)=2t-4
a⋅(b-2)=3b

Question

$$1 + \sqrt { 6 } d \sqrt { 2 } + \sqrt { 3 }$$

Answer

$$1+2*sqrt(3)*t+Co*e*sqrt(3)*m*p*a*r^2$$

Solution


Simplify  \(\sqrt{6}t\sqrt{2}\)  to  \(\sqrt{6\times 2}t\).
\[1+\sqrt{6\times 2}t+\sqrt{3}Comparer\]
Simplify  \(6\times 2\)  to  \(12\).
\[1+\sqrt{12}t+\sqrt{3}Comparer\]
Simplify  \(\sqrt{12}\)  to  \(2\sqrt{3}\).
\[1+2\sqrt{3}t+\sqrt{3}Comparer\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[1+2\sqrt{3}t+\sqrt{3}Compa{r}^{2}e\]
Regroup terms.
\[1+2\sqrt{3}t+Coe\sqrt{3}mpa{r}^{2}\]
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