How to solve 10/1=1/2(-2-6x)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 10/1=1/2(-2-6x) | Equatix

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Question

$$10/1=1/2(-2-6x)$$

Solve for x

$x = -\frac{11}{3} = -3\frac{2}{3} \approx -3.666666667$

Steps for Solving Linear Equation

Anything divided by one gives itself.

$$10=\frac{1}{2}\left(-2-6x\right)$$

Use the distributive property to multiply $\frac{1}{2}$ by $-2-6x$.

$$10=\frac{1}{2}\left(-2\right)+\frac{1}{2}\left(-6\right)x$$

Multiply $\frac{1}{2}$ and $-2$ to get $\frac{-2}{2}$.

$$10=\frac{-2}{2}+\frac{1}{2}\left(-6\right)x$$

Divide $-2$ by $2$ to get $-1$.

$$10=-1+\frac{1}{2}\left(-6\right)x$$

Multiply $\frac{1}{2}$ and $-6$ to get $\frac{-6}{2}$.

$$10=-1+\frac{-6}{2}x$$

Divide $-6$ by $2$ to get $-3$.

$$10=-1-3x$$

Swap sides so that all variable terms are on the left hand side.

$$-1-3x=10$$

Add $1$ to both sides.

$$-3x=10+1$$

Add $10$ and $1$ to get $11$.

$$-3x=11$$

Divide both sides by $-3$.

$$x=\frac{11}{-3}$$

Fraction $\frac{11}{-3}$ can be rewritten as $-\frac{11}{3}$ by extracting the negative sign.

$$x=-\frac{11}{3}$$

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