Question

$$10\cdot=S+(1d-1)\times3$$

Answer

S=-30*(d-1)

Solution


Simplify  \(1\times d\)  to  \(d\).
\[10=S+(d-1)\times 3\]
Regroup terms.
\[10=S+3(d-1)\]
Subtract \(3(d-1)\) from both sides.
\[10\times -3(d-1)=S\]
Simplify  \(10\times -3(d-1)\)  to  \(-30(d-1)\).
\[-30(d-1)=S\]
Switch sides.
\[S=-30(d-1)\]