Solve 10gamma0.8x + 1.25 = 2x + 0.05 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$10\gamma0.8x+1.25=2x+0.05$$

Solve for x

$x=-\frac{3}{5\left(4\gamma _{0}-1\right)}$
$\gamma _{0}\neq \frac{1}{4}$

Steps for Solving Linear Equation

Multiply $10$ and $0.8$ to get $8$.

$$8\gamma _{0}x+1.25=2x+0.05$$

Subtract $2x$ from both sides.

$$8\gamma _{0}x+1.25-2x=0.05$$

Subtract $1.25$ from both sides.

$$8\gamma _{0}x-2x=0.05-1.25$$

Subtract $1.25$ from $0.05$ to get $-1.2$.

$$8\gamma _{0}x-2x=-1.2$$

Combine all terms containing $x$.

$$\left(8\gamma _{0}-2\right)x=-1.2$$

Divide both sides by $-2+8\gamma _{0}$.

$$\frac{\left(8\gamma _{0}-2\right)x}{8\gamma _{0}-2}=-\frac{1.2}{8\gamma _{0}-2}$$

Dividing by $-2+8\gamma _{0}$ undoes the multiplication by $-2+8\gamma _{0}$.

$$x=-\frac{1.2}{8\gamma _{0}-2}$$

Divide $-1.2$ by $-2+8\gamma _{0}$.

$$x=-\frac{3}{5\left(4\gamma _{0}-1\right)}$$

Solve for γ_0

$\gamma _{0}=0.25-\frac{3}{20x}$
$x\neq 0$

Steps for Solving Linear Equation

Multiply $10$ and $0.8$ to get $8$.

$$8\gamma _{0}x+1.25=2x+0.05$$

Subtract $1.25$ from both sides.

$$8\gamma _{0}x=2x+0.05-1.25$$

Subtract $1.25$ from $0.05$ to get $-1.2$.

$$8\gamma _{0}x=2x-1.2$$

The equation is in standard form.

$$8x\gamma _{0}=2x-1.2$$

Divide both sides by $8x$.

$$\frac{8x\gamma _{0}}{8x}=\frac{2x-1.2}{8x}$$

Dividing by $8x$ undoes the multiplication by $8x$.

$$\gamma _{0}=\frac{2x-1.2}{8x}$$

Divide $2x-1.2$ by $8x$.

$$\gamma _{0}=\frac{1}{4}-\frac{3}{20x}$$